Wednesday, May 18, 2011

Zeta-Gamma Function

GZ.ID.1:  Fundamental Zeta-Gamma  function
the relation between Zeta function and Gamma function can be represented in the following form:




Proof

Given
(1)
(2)

 (3)

(4)
substituting (4) into (3)


(5)


(6)

(7)

(8)
Based on Geometric Series of Exponential (GS.ID.2),

(9)

(10)

(11) 
based on (10) and (11) , 


 
 (12) 
 
(13) 
(14) 
 
 (15) 

 (16) 

GZ.ID.2:   Zeta-Gamma  function (Trigonometric)



Proof

Given

(1)
 (2)
(3)


(4)
substituting (4) into (1) ,

(5)
(6)


(7)
substituting (2) into (7) :
(8)

from (16),  at (GZ.ID.1)  ,

(9)
(10)
based on (9) and (10) , then


 multiplying and dividing the denominator by   ,   and based on (3) therefore 



GZ.ID.3:   Zeta-Gamma  function

 
Given


(1)


 (2)

 (3)
substitute (3) into (2) , 

(4)

 (5)

(6)
differentiate (6) ,

(7)
substitute (7) into (5) ,

(8)



Wednesday, May 4, 2011

Gamma Function

firstly , I recommend you  to read these  Gamma function   to have fundamental understanding of the Gamma function.

G.ID.1: Differentiation (integral representation)

 

differentiate gamma function in term of x variable 






if x=1


G.ID.2: integral representation
 

proof

given that

variable substitution
(1)

(2)
from (1), lower and upper integrals boundaries change

 

 
 (3)
  (4)
 
  (5)



G.ID.3: integral representation

 

proof

given that
variable substitution
 

 

 



G.ID.4: Weierstrass Identity



= Euler–Mascheroni constant

Given


Proof

 (1)


(2)

(3)


the cancels out, and based on (3) , therefore,



(4)





 (5)
multiply 4 by 5 , therefore

 
 (6)

 (7)

(8)

= Euler–Mascheroni constant

therefore;


(9)






G.ID.5: Reflection Formula





Given

(1)

 
(2)

 Proof
multiplication of (1) and (2)

 
(3)

 sine identity
(4)
Recurrence identity of gamma function
(5)

based on (3) and (4) , (5)

(5)

(6)


replace x and (1-x) with the following identities


(7)

therefore

(8)




(9)
substituting  (9) into (8) results in 








G.ID.6: Recurrence  Identity

 

given
proof





if s=s+1/2

integrating by parts results:







after n times of integration by parts:


similarly for s+1/3 and s+1/4









G.ID.7: 




proof



(1)




(2)


(3)


(4)


(5)


(6)